How do I unwrap optionals safely with if let?

In Swift, unwrapping optionals safely can be done using the `if let` statement. This approach allows you to check whether an optional contains a value and, if it does, assign that value to a new constant. This prevents runtime errors that can occur when trying to use nil values.

Here’s a simple example of using `if let` for optional unwrapping:


        let optionalString: String? = "Hello, Swift!"
        
        if let unwrappedString = optionalString {
            print(unwrappedString) // Output: Hello, Swift!
        } else {
            print("optionalString was nil")
        }