How do I fix 'Value of optional type must be unwrapped'?

To fix the error 'Value of optional type must be unwrapped' in Swift, you can use optional binding (if let or guard let), optional chaining, or forced unwrapping.


        <?php
        $optionalString = "Hello, World!";
        
        // Using if statement to check if the value is null
        if ($optionalString !== null) {
            echo $optionalString; // Output: Hello, World!
        }
        ?>

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`. - The PHP example of optional handling is inside a `` block with the specified class.