How do I use return type deduction in C++14?

In C++14, return type deduction allows functions to automatically deduce their return type based on the return statement. This feature simplifies code and enhances type safety.
C++14, return type deduction, auto, type safety, modern C++
// C++14 example of return type deduction #include #include auto add(int a, int b) { return a + b; // The return type is deduced to int } auto get_vector() { return std::vector{1, 2, 3}; // The return type is deduced to std::vector } int main() { auto sum = add(5, 3); std::cout << "Sum: " << sum << std::endl; auto vec = get_vector(); std::cout << "Vector: "; for (const auto& val : vec) { std::cout << val << " "; } std::cout << std::endl; return 0; }

C++14 return type deduction auto type safety modern C++

Related Questions

How do I avoid rehashing overhead with std::set in multithreaded code?

How do I find elements with custom comparators with std::set for embedded targets?

How do I erase elements while iterating with std::set for embedded targets?

How do I provide stable iteration order with std::unordered_map for large datasets?

How do I reserve capacity ahead of time with std::unordered_map for large datasets?

How do I erase elements while iterating with std::unordered_map in multithreaded code?

How do I provide stable iteration order with std::map for embedded targets?

How do I provide stable iteration order with std::map in multithreaded code?

How do I avoid rehashing overhead with std::map in performance-sensitive code?

How do I merge two containers efficiently with std::map for embedded targets?