Merging two std::deque containers in C++ can be challenging in multithreaded environments; however, efficient techniques can be employed to ensure that performance is optimized while maintaining thread safety.
Using locks or synchronization mechanisms, you can safely merge two deques. Here’s an example illustrating how to do that:
#include <iostream>
#include <deque>
#include <mutex>
#include <thread>
std::mutex mergeMutex;
void mergeDeques(std::deque<int>& dest, std::deque<int>& src) {
std::lock_guard<std::mutex> lock(mergeMutex);
dest.insert(dest.end(), src.begin(), src.end());
}
void threadFunction(std::deque<int>& dest, std::deque<int>& src) {
mergeDeques(dest, src);
}
int main() {
std::deque<int> deque1 = {1, 2, 3};
std::deque<int> deque2 = {4, 5, 6};
std::deque<int> mergedDeque;
std::thread t1(threadFunction, std::ref(mergedDeque), std::ref(deque1));
std::thread t2(threadFunction, std::ref(mergedDeque), std::ref(deque2));
t1.join();
t2.join();
for (const auto& item : mergedDeque) {
std::cout << item << " ";
}
std::cout << std::endl;
return 0;
}
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