Erasing elements from a `std::deque` while iterating can lead to iterator invalidation issues. To safely remove elements, it's best to use the `erase` method combined with a loop that properly manages the iterator position. Below is an example that demonstrates how to do this effectively.
#include <deque>
#include <iostream>
int main() {
std::deque<int> myDeque = {1, 2, 3, 4, 5};
for (auto it = myDeque.begin(); it != myDeque.end(); ) {
if (*it % 2 == 0) { // Condition to remove even numbers
it = myDeque.erase(it); // Erase and get new iterator
} else {
++it; // Move to the next element
}
}
// Output remaining elements
for (const auto& value : myDeque) {
std::cout << value << ' ';
}
return 0;
}
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